5m^2+30m-35=0

Solution for 5m^2+30m-35=0 equation:

5m^2+30m-35=0

a = 5; b = 30; c = -35;
Δ = b2-4ac
Δ = 302-4·5·(-35)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-40}{2*5}=\frac{-70}{10}
=-7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+40}{2*5}=\frac{10}{10}
=1
$